DATE_SUB

Subtract the time interval or date interval from the provided date or date with time (timestamp/datetime).

Analyze Syntax

func.date_sub(<unit>, <value>,  <date_or_time_expr>)

Analyze Examples

func.date_sub('YEAR', 1, func.to_date('2018-01-02'))
+------------------------------------------------------+
| func.date_sub('YEAR', 1, func.to_date('2018-01-02')) |
+------------------------------------------------------+
| 2017-01-02                                           |
+------------------------------------------------------+

SQL Syntax

DATE_SUB(<unit>, <value>,  <date_or_time_expr>)

Arguments

ArgumentsDescription
<unit>Must be of the following values: YEAR, QUARTER, MONTH, DAY, HOUR, MINUTE and SECOND
<value>This is the number of units of time that you want to add. For example, if you want to add 2 days, this will be 2.
<date_or_time_expr>A value of DATE or TIMESTAMP type

Return Type

The function returns a value of the same type as the <date_or_time_expr> argument.

SQL Examples

Query:

SELECT date_sub(YEAR, 1, to_date('2018-01-02'));
+---------------------------------------------------+
| DATE_SUB(YEAR, INTERVAL 1, to_date('2018-01-02')) |
+---------------------------------------------------+
| 2017-01-02                                        |
+---------------------------------------------------+
Last modified June 12, 2024 at 9:53 PM EST: updating datetime functions (f087f54)